Integrand size = 21, antiderivative size = 131 \[ \int \frac {\left (c+d x^2\right )^{3/2}}{\left (a+b x^2\right )^2} \, dx=\frac {(b c-a d) x \sqrt {c+d x^2}}{2 a b \left (a+b x^2\right )}+\frac {\sqrt {b c-a d} (b c+2 a d) \arctan \left (\frac {\sqrt {b c-a d} x}{\sqrt {a} \sqrt {c+d x^2}}\right )}{2 a^{3/2} b^2}+\frac {d^{3/2} \text {arctanh}\left (\frac {\sqrt {d} x}{\sqrt {c+d x^2}}\right )}{b^2} \]
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Time = 0.06 (sec) , antiderivative size = 131, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.286, Rules used = {424, 537, 223, 212, 385, 211} \[ \int \frac {\left (c+d x^2\right )^{3/2}}{\left (a+b x^2\right )^2} \, dx=\frac {\sqrt {b c-a d} (2 a d+b c) \arctan \left (\frac {x \sqrt {b c-a d}}{\sqrt {a} \sqrt {c+d x^2}}\right )}{2 a^{3/2} b^2}+\frac {x \sqrt {c+d x^2} (b c-a d)}{2 a b \left (a+b x^2\right )}+\frac {d^{3/2} \text {arctanh}\left (\frac {\sqrt {d} x}{\sqrt {c+d x^2}}\right )}{b^2} \]
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Rule 211
Rule 212
Rule 223
Rule 385
Rule 424
Rule 537
Rubi steps \begin{align*} \text {integral}& = \frac {(b c-a d) x \sqrt {c+d x^2}}{2 a b \left (a+b x^2\right )}+\frac {\int \frac {c (b c+a d)+2 a d^2 x^2}{\left (a+b x^2\right ) \sqrt {c+d x^2}} \, dx}{2 a b} \\ & = \frac {(b c-a d) x \sqrt {c+d x^2}}{2 a b \left (a+b x^2\right )}+\frac {d^2 \int \frac {1}{\sqrt {c+d x^2}} \, dx}{b^2}+\frac {((b c-a d) (b c+2 a d)) \int \frac {1}{\left (a+b x^2\right ) \sqrt {c+d x^2}} \, dx}{2 a b^2} \\ & = \frac {(b c-a d) x \sqrt {c+d x^2}}{2 a b \left (a+b x^2\right )}+\frac {d^2 \text {Subst}\left (\int \frac {1}{1-d x^2} \, dx,x,\frac {x}{\sqrt {c+d x^2}}\right )}{b^2}+\frac {((b c-a d) (b c+2 a d)) \text {Subst}\left (\int \frac {1}{a-(-b c+a d) x^2} \, dx,x,\frac {x}{\sqrt {c+d x^2}}\right )}{2 a b^2} \\ & = \frac {(b c-a d) x \sqrt {c+d x^2}}{2 a b \left (a+b x^2\right )}+\frac {\sqrt {b c-a d} (b c+2 a d) \tan ^{-1}\left (\frac {\sqrt {b c-a d} x}{\sqrt {a} \sqrt {c+d x^2}}\right )}{2 a^{3/2} b^2}+\frac {d^{3/2} \tanh ^{-1}\left (\frac {\sqrt {d} x}{\sqrt {c+d x^2}}\right )}{b^2} \\ \end{align*}
Time = 0.48 (sec) , antiderivative size = 148, normalized size of antiderivative = 1.13 \[ \int \frac {\left (c+d x^2\right )^{3/2}}{\left (a+b x^2\right )^2} \, dx=\frac {\frac {b (b c-a d) x \sqrt {c+d x^2}}{a \left (a+b x^2\right )}-\frac {\sqrt {b c-a d} (b c+2 a d) \arctan \left (\frac {a \sqrt {d}+b x \left (\sqrt {d} x-\sqrt {c+d x^2}\right )}{\sqrt {a} \sqrt {b c-a d}}\right )}{a^{3/2}}-2 d^{3/2} \log \left (-\sqrt {d} x+\sqrt {c+d x^2}\right )}{2 b^2} \]
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Time = 3.05 (sec) , antiderivative size = 114, normalized size of antiderivative = 0.87
method | result | size |
pseudoelliptic | \(-\frac {-2 d^{\frac {3}{2}} \operatorname {arctanh}\left (\frac {\sqrt {d \,x^{2}+c}}{x \sqrt {d}}\right )-\frac {\left (a d -b c \right ) \left (-\frac {b \sqrt {d \,x^{2}+c}\, x}{b \,x^{2}+a}-\frac {\left (2 a d +b c \right ) \operatorname {arctanh}\left (\frac {\sqrt {d \,x^{2}+c}\, a}{x \sqrt {\left (a d -b c \right ) a}}\right )}{\sqrt {\left (a d -b c \right ) a}}\right )}{a}}{2 b^{2}}\) | \(114\) |
default | \(\text {Expression too large to display}\) | \(3387\) |
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Time = 0.35 (sec) , antiderivative size = 903, normalized size of antiderivative = 6.89 \[ \int \frac {\left (c+d x^2\right )^{3/2}}{\left (a+b x^2\right )^2} \, dx=\left [\frac {4 \, {\left (b^{2} c - a b d\right )} \sqrt {d x^{2} + c} x + 4 \, {\left (a b d x^{2} + a^{2} d\right )} \sqrt {d} \log \left (-2 \, d x^{2} - 2 \, \sqrt {d x^{2} + c} \sqrt {d} x - c\right ) + {\left (a b c + 2 \, a^{2} d + {\left (b^{2} c + 2 \, a b d\right )} x^{2}\right )} \sqrt {-\frac {b c - a d}{a}} \log \left (\frac {{\left (b^{2} c^{2} - 8 \, a b c d + 8 \, a^{2} d^{2}\right )} x^{4} + a^{2} c^{2} - 2 \, {\left (3 \, a b c^{2} - 4 \, a^{2} c d\right )} x^{2} - 4 \, {\left (a^{2} c x - {\left (a b c - 2 \, a^{2} d\right )} x^{3}\right )} \sqrt {d x^{2} + c} \sqrt {-\frac {b c - a d}{a}}}{b^{2} x^{4} + 2 \, a b x^{2} + a^{2}}\right )}{8 \, {\left (a b^{3} x^{2} + a^{2} b^{2}\right )}}, \frac {4 \, {\left (b^{2} c - a b d\right )} \sqrt {d x^{2} + c} x - 8 \, {\left (a b d x^{2} + a^{2} d\right )} \sqrt {-d} \arctan \left (\frac {\sqrt {-d} x}{\sqrt {d x^{2} + c}}\right ) + {\left (a b c + 2 \, a^{2} d + {\left (b^{2} c + 2 \, a b d\right )} x^{2}\right )} \sqrt {-\frac {b c - a d}{a}} \log \left (\frac {{\left (b^{2} c^{2} - 8 \, a b c d + 8 \, a^{2} d^{2}\right )} x^{4} + a^{2} c^{2} - 2 \, {\left (3 \, a b c^{2} - 4 \, a^{2} c d\right )} x^{2} - 4 \, {\left (a^{2} c x - {\left (a b c - 2 \, a^{2} d\right )} x^{3}\right )} \sqrt {d x^{2} + c} \sqrt {-\frac {b c - a d}{a}}}{b^{2} x^{4} + 2 \, a b x^{2} + a^{2}}\right )}{8 \, {\left (a b^{3} x^{2} + a^{2} b^{2}\right )}}, \frac {2 \, {\left (b^{2} c - a b d\right )} \sqrt {d x^{2} + c} x + {\left (a b c + 2 \, a^{2} d + {\left (b^{2} c + 2 \, a b d\right )} x^{2}\right )} \sqrt {\frac {b c - a d}{a}} \arctan \left (\frac {{\left ({\left (b c - 2 \, a d\right )} x^{2} - a c\right )} \sqrt {d x^{2} + c} \sqrt {\frac {b c - a d}{a}}}{2 \, {\left ({\left (b c d - a d^{2}\right )} x^{3} + {\left (b c^{2} - a c d\right )} x\right )}}\right ) + 2 \, {\left (a b d x^{2} + a^{2} d\right )} \sqrt {d} \log \left (-2 \, d x^{2} - 2 \, \sqrt {d x^{2} + c} \sqrt {d} x - c\right )}{4 \, {\left (a b^{3} x^{2} + a^{2} b^{2}\right )}}, \frac {2 \, {\left (b^{2} c - a b d\right )} \sqrt {d x^{2} + c} x - 4 \, {\left (a b d x^{2} + a^{2} d\right )} \sqrt {-d} \arctan \left (\frac {\sqrt {-d} x}{\sqrt {d x^{2} + c}}\right ) + {\left (a b c + 2 \, a^{2} d + {\left (b^{2} c + 2 \, a b d\right )} x^{2}\right )} \sqrt {\frac {b c - a d}{a}} \arctan \left (\frac {{\left ({\left (b c - 2 \, a d\right )} x^{2} - a c\right )} \sqrt {d x^{2} + c} \sqrt {\frac {b c - a d}{a}}}{2 \, {\left ({\left (b c d - a d^{2}\right )} x^{3} + {\left (b c^{2} - a c d\right )} x\right )}}\right )}{4 \, {\left (a b^{3} x^{2} + a^{2} b^{2}\right )}}\right ] \]
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\[ \int \frac {\left (c+d x^2\right )^{3/2}}{\left (a+b x^2\right )^2} \, dx=\int \frac {\left (c + d x^{2}\right )^{\frac {3}{2}}}{\left (a + b x^{2}\right )^{2}}\, dx \]
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\[ \int \frac {\left (c+d x^2\right )^{3/2}}{\left (a+b x^2\right )^2} \, dx=\int { \frac {{\left (d x^{2} + c\right )}^{\frac {3}{2}}}{{\left (b x^{2} + a\right )}^{2}} \,d x } \]
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Leaf count of result is larger than twice the leaf count of optimal. 315 vs. \(2 (109) = 218\).
Time = 0.31 (sec) , antiderivative size = 315, normalized size of antiderivative = 2.40 \[ \int \frac {\left (c+d x^2\right )^{3/2}}{\left (a+b x^2\right )^2} \, dx=-\frac {d^{\frac {3}{2}} \log \left ({\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{2}\right )}{2 \, b^{2}} - \frac {{\left (b^{2} c^{2} \sqrt {d} + a b c d^{\frac {3}{2}} - 2 \, a^{2} d^{\frac {5}{2}}\right )} \arctan \left (\frac {{\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{2} b - b c + 2 \, a d}{2 \, \sqrt {a b c d - a^{2} d^{2}}}\right )}{2 \, \sqrt {a b c d - a^{2} d^{2}} a b^{2}} - \frac {{\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{2} b^{2} c^{2} \sqrt {d} - 3 \, {\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{2} a b c d^{\frac {3}{2}} + 2 \, {\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{2} a^{2} d^{\frac {5}{2}} - b^{2} c^{3} \sqrt {d} + a b c^{2} d^{\frac {3}{2}}}{{\left ({\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{4} b - 2 \, {\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{2} b c + 4 \, {\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{2} a d + b c^{2}\right )} a b^{2}} \]
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Timed out. \[ \int \frac {\left (c+d x^2\right )^{3/2}}{\left (a+b x^2\right )^2} \, dx=\int \frac {{\left (d\,x^2+c\right )}^{3/2}}{{\left (b\,x^2+a\right )}^2} \,d x \]
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